WebWork Related Rates #8 – hint

(Try not to read this hint unless you’ve already attempted the problem.) Everyone’s numbers for this problem might be different, but the main ideas will be the same.

You have an upside-down cone and water is flowing in and out of it. You’re told that water is being pumped in at a constant rate, and then asked to find what that rate is. At first I think it’d be helpful to consider V_{in}(t), the function that models the volume of water that’s flowed in at time t, and V_{out}(t), the function that models the amount of water that’s flowed out at time t. My version of the question says that water is flowing out at 10,000 cubic cm per minute, so that means \frac{dV_{out}}{dt} = 10,000. Since it says that water is flowing in at a constant rate, I’m going to let \frac{dV_{in}}{dt}=c; then my job is to find c.

If I let V(t) be the volume of the water that’s actually in the tank at time t, then V(t)=V_{in}(t)-V_{out},Ā (this assumes that at time t=0 there is no water in the tank, but this assumption won’t end up mattering) so \frac{dV}{dt}= \frac{dV_{in}}{dt}-\frac{dV_{in}}{dt}.

Hopefully this set-up is enough to help you get started!

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Today’s missed class – reading and exerices

It seems I’ve mostly recovered from whatever was making me feel bad this morning. Thanks for your well-wishes and sorry you had to wake up early today for nothing! I hope you’re all working hard on your take-home tests and thinking about group project topics. One of your WebWork sets due next Tuesday includes material that would have been covered during today’s class. Below, I’ll give you a few short readings/exercises to do before Monday’s class so that today’s missed class doesn’t put us too far behind schedule. It shouldn’t take you more than 15 minutes to go through the whole thing

3.5 Higher derivatives

Some of you have been anticipating this for a while: since the derivative f'(x) of a function f(x) is itself a function, you can take the derivative of the derivative. We call the derivative of the derivative of f(x) the second derivative of f(x) and denote it by f''(x). Similarly, the third derivative of f(x), is the derivative of the derivative of the derivative of f(x). The third derivative is denoted by f'''(x) or sometimes f^{(3)}(x). The nth derivative is usually denoted f^{(n)}(x). Here, you can imagine n is any positive integer, but you can include n=0 if you define the zeroth derivative of f(x) as f(x) itself.

Exercise: Let f(x) = \sin(x). Find all the derivatives of f(x).

An application: Remember that getting-caught-speeding example from the first week of class. In groups you turned a story about driving into a position-versus-time graph. The first part of the story said something like, “You pulled out of the driveway slowly and then sped up.” Every group’s graph started off increasing slowly and then curved up and increased more quickly. First, remember that the derivative of a position function is an instantaneous velocity function. Since the graph for this portion is increasing, the velocity is positive…you’re driving away from your house so the distance between you and the house is increasing. Ā Second, the derivative of a velocity function is the instantaneous rate of change of velocity…also known as acceleration. Ā Since you were speeding up, the acceleration is positive…so the position graph is curving up. (We say this part of the graph is concave up. If you were slowing down, but still moving forward, the velocity would be positive and the graph of the position function increasing, but the acceleration would be negative so the graph of the position function would be concave down.)

Another similar example is an object dropped from rest. The distance the object falls in t seconds is s(t)=4.9t^2 meters. Its instantaneous velocity is v(t)=9.8t m/s and its instantaneous acceleration is a(t)=9.8 m/s^2. If you’ve ever taken a physics course, you might recognize this as the constant acceleration due to gravity, sometimes denoted by g.

4.1 Linearization

Shifting gears a little, remember that the tangent line to a curve at a point is the line that best approximates the curve at that point. As long as the curve is smooth, there is a tangent line and we say that the curve is locally linear. Linear functions are among the easiest functions to do calculations with, so (if you can tolerate a little error) you might use the tangent line to the graph of a function rather than the function itself. This will only work if the only points you’re interested in are close enough to the point of tangency.

Exercise: Head on over to DesmosĀ or pull out your graphing calculator.

  1. Graph the function f(x) = \sqrt{x}.
  2. We’ll focus on the point (4,2). Zoom in as much as you can; notice that the graph is approximately a line.
  3. By hand, find the equation of the tangent line to the graph ofĀ f(x) = \sqrt{x} atĀ (4,2).
  4. Graph the tangent line and zoom in onĀ (4,2); notice that the graph of the function and the tangent line are approximately the same thing. Zoom out and notice that the graphs are far apart for points far away fromĀ (4,2).
  5. Use your calculator to find the y-coordinate of the point on the graph of f(x) with x-coordinate 4.1. (the calculator will spit out a decimal approximation; that’s okay, just record as many decimal places as you can tolerate.)
  6. By hand, find the y-coordinate of the point on the tangent line with x-coordinate 4.1. (You’ll probably have to remember how to perform long division of numbers when there’s a decimal.)
  7. Compare your answers for 5 and 6 by subtracting one from the other. If everything went as planned, the difference should be small. This is what is meant by the error.

The point of this exercise is that you were able to approximate \sqrt{4.1} by hand, because 4.1 is close to 4, whose square root is easy.

There’s nothing special about the square root function…you can approximate values for other functions too. The linearization of a function f(x) at a point x=a is L(x)=f(a)+f'(a)(x-a). Notice that the graph of the linearization is just the tangent line to f(x) at the point x=a.

Exercise: Use the same steps above to approximate \sin(3.14). (Notice that 3.14 is close to, but not equal to \pi.) Calculate the error.

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WebWork for next week

Third post of the day!

Since I expect many of you will be working on test #1, round 2 for Monday….

  • There will be no written homework component this week.
  • WebWork will be due Tuesday night instead of Sunday night. You’ll probably want to at least try some of the problems on the sets RatesofChange-HigherDeriv, ImplicitĀ Differentiation, and Related_Rates before Monday’s class, though.

FYI, We’ll cover higher derivatives (pretty easy) and linearization (also pretty easy) in class this Wednesday.

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Group Projects – preliminary ideas

The timeline for the group projects will be laid out for you soon, but we should figure out two things as soon as we can:

  1. Who’s in what group?
  2. What’s that group’s topic?

I just posted preliminary topic ideas and project descriptions under Group Projects. As I described in class, I haven’t yet been able to come up with something more creative on my own. I’ll keep thinking and asking all my nerd friends for ideas! If any of the four topics listed on that page looks like it might be at all interesting to you, great. All you have to do for now is indicate your preference by posting a comment. If you think you have a better idea, that’s wonderful. Post a comment describing the idea so we can start figuring out the details of it, and so you can start recruiting classmates to join your group. We have tons of flexibility topic-wise so even though the four ideas are all applications of calculus, we can also think about having projects that are more theory based.

Ideally, there will be groups of 3 or 4. If one topic is overwhelmingly popular, we can have two groups working on the same topic, but hopefully from different perspectives.

I’d like to have a sense of the answers for 1 and 2 above by next week.

 

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Test #1 – extra-credit assignment

As announced in class today, you can resubmit a completed test #1 to boost your test grade up to 20%. This extra-credit assignment has two components:

  • Print out and complete test #1. You are encouraged to make a rough copy and a good copy. Your work should be crystal clear; you should only be submitting answers that you think should receive full credit. You may not collaborate with your classmates…this is still a test so should include only your own work. You may consult your notes if absolutely necessary, but in this case you must include a note saying that’s what you did. You don’t need to give yourself a time limit. Do not put your name on your paper. (I’ll have a system to keep track of which paper belongs to which person.)
  • Your classmates will be grading your work. The grader will not know whose paper he or she is grading. Official solutions and grading schemes will be provided. It’s easier to grade work that is complete and correct, which is one of the reasons you should not rely on partial credit for this assignment. Another reason is that if you provide a solution that differs from the one on the official solution set, you’ll want the grader to be able to understand that what you did is still correct.

Your completed test is due next Monday, March 24. After that, you’ll have one week to grade your classmate’s test.

Please do not distribute the linked PDF: test1

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Test

Can you post a copy of the test? šŸ˜€

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Helpp

1394565332312

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Question regarding the WW HW

Alright lads,

Given y=(x+sinx)^4

Find g(x) and f(x) such that f 0 g (i.e. f(g(x))) =y. Compute the derivative using chain rule.

I got the answer through observation, however I didn’t have a solid method,

We know f o g= f(g(x))=y

I have to find f(x) and g(x) such that f(g(x))=y (There are 2 ‘machines’ at work here and the order matters).

The first ‘machine/function’ is g(x)=x+sinx
Put in an ‘x’ into this ‘machine’ and out comes a ‘x+sinx’

Now for the second ‘machine’, f(x)=x4
Put in an ‘x’ into this machine and out comes a ‘x^4’
Similarly put in an ‘x+sinx’ and out comes a ‘(x+sinx)^4’

This is a how I’m thinking it in my head but I don’t know how I ‘observed’ the two functions to be f(x)=x^4 and g(x)=x+sinx. I looked at (x+sinx)^4 and ‘broke it down’ in my head. My question is, is there a routine way to calculate this for more complicated polynomials?

Finding the derivative was easy, so no worries there.

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Test #1 Review Question

I have not gotten the hang of latex yet, so I hope you’ll still be able to understand the question. This also may be a fairly easy question.

Use the appropriate rules or combination of rules to find:

(d/dx)(x^2sin(x)+2xcos(x)-2sin(x))

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Review Question

Solve the following question by using chain rule.

y=((x-3)/(x+3))^4

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