(pronounced LAY-teck) is a commonly used language for typesetting math. There are many ways to use to create professional looking documents (most involve installing an implementation on your computer) but you can also use to type math right in your OpenLab posts.

Professor Reitz has some great instructions for using on the OpenLab here (scroll to “Typing math on the OpenLab”).

It can take some getting used to, your homework is to **practice by submitting a comment on this post**. Don’t worry about typing something that makes any mathematical sense, just try typing anything. Play around and make a giant mess in these comments. If something doesn’t work at first, don’t worry; just try again. (Note that your first OpenLab comment will have to be approved before it appears.)

You can mouse-over something to see what LaTeX code was. For example, mouse-over this: to see what I entered.

If you submit something that LaTeX doesn’t understand, it will display “formula does not parse” but you can also mouse-over that to see what was submitted.

Other resources:

- The Not So Short Introduction to
- The Comprehensive Symbol List
- A shorter symbol list
- Overleaf (writing full documents and collaborating online)
- The Project (an overview)

This is a normal comment.

OMG

$/Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena

You mean

$latex \Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena

Oh wait I mean

$latex/Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena

$latex/Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena$

Nice! If I were giving this question on a test, I’d probably put parentheses around the integrand to make it extra clear that the +5 is included:

Close but it looks like your slashes are going the wrong way

I also changed your upper case Mu and Nu to lower case (the upper case ones are just M and N)

Here is a differential equation

Close! To get the square root symbol, don’t forget the backslash \sqrt instead of sqrt.

(I know I said that it doesn’t matter if your math makes any sense, but I can’t stop myself from pointing out that this is not usually what we mean by “differential equation” because no derivatives appear in it. If is a function of , then you could argue that is the zero-th derivative of itself, which would be correct, but it might make me roll my eyes.)

Agreed, I just noticed differential equation must have derivative in it, and my equation doesn’t have it . Actually when I wrote it I was focusing on the latex command more then the formula itself.

$latex\sqrt{y}2x+xy”=1 $

$ latex\sqrt{y}2x+xy”=1 $

So close! Delete the space before “latex” and add a space after it; replace your double quotation with two single ones ‘

$ latex\sqrt{y}2x+xy”=1\$

$latex\sqrt{y}2x+xy”=1\$

$latex\sqrt{y}2x+xy”=1\ $

$latex\sqrt{y}2x+xy”=1\

what a big mess I just created

one more last time

$Latex \sqrt{y}2x+xy”=1$

Haha, now just make the L on “Latex” lower case, and you’re golden!

I bet you meant

$ Latex setminus

Wow, took a lot longer than expected -.-

Looks good! Once you get the hang of typing in Latex, it becomes much easier; the first attempts always take the longest…but practicing is the point of this exercise!

Beautiful!

$latex/sqrt{x^2+1}+/sqrt[7]{x^3+5}$

Nice!

\intfrac{1}{arcsintheta}dx

$latex\intfrac{1}{arcsintheta}dx

$latex\intfrac{1}{arcsintheta}dx$

No luck for me.

$latex\int\frac{1}{arcsintheta}dx$

You got it eventually! Nice work!

It’s not important for this exercise, but I must point out that the variable in your integrand doesn’t match your variable of integration , so if you were to evaluate your integral, your answer would just be .

Just FYI, Latex knows the trigononometric (and inverse trigonometric) functions, so there is an \arcsin macro. It might not look like a big difference, but we typically prefer the roman characters to the italic ones:

instead of

$latex\sqrt{9}$

There ya go!

$latex/sqrt{x+3}

$latex /sqrt{5}/

$latex \sqrt{15}\

$latex \sqrt{6}/

Looks good!

Lovely!

$latex \sqrt{5}

Close! Don’t forget to close up your Latex dollar signs:

$latex \sqrt{x^3 + / 1}

Nice! I’m not sure if you meant to have a fraction as a radicand. If so, you can use the Latex macro \frac:

Great!

$ Latex (n^2-3n+4)/2$

$ Latex /(n^2-3n+4)/2$

$ latex (n^2-3n+4)/2$

$ latex/(n^2-3n+4)/2

$ latex/(n^2-3n+4)/2$

So close! Move the space from before “latex” to after it.

$latex\ \If \triangle ABC \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangleABC \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle.$

$latex\ \If \triangle ABC \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangleABC \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle. $

$latex\ \If \triangle ABC \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangleABC \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle. $

$latex\ If \triangle ABC \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangleABC \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle.$

$latex\ If \triangle{ABC} \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangle{ABC} \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle.$

$latex\ If \triangle {ABC} \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangle {ABC} \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle.$