Fall 2016 - Professor Kate Poirier

$\LaTeX$ (pronounced LAY-teck) is a commonly used language for typesetting math. There are many ways to use $\LaTeX$ to create professional looking documents (most involve installing an implementation on your computer) but you can also use $\LaTeX$ to type math right in your OpenLab posts.

Professor Reitz has some great instructions for using $\LaTeX$ on the OpenLab here (scroll to “Typing math on the OpenLab”).

It can take some getting used to, your homework is to practice by submitting a comment on this post. Don’t worry about typing something that makes any mathematical sense, just try typing anything. Play around and make a giant mess in these comments. If something doesn’t work at first, don’t worry; just try again. (Note that your first OpenLab comment will have to be approved before it appears.)

You can mouse-over something to see what LaTeX code was. For example, mouse-over this: $\frac{d}{dx} \left( \int_a^x f(t)dt \right) = F(x)$ to see what I entered.

If you submit something that LaTeX doesn’t understand, it will display “formula does not parse” but you can also mouse-over that to see what was submitted.

Other resources:

1. Kate Poirier

This is a normal comment.

$\sqrt{2}$

• Kate Poirier

$\swrt{2}$

2. Josiel

OMG

$\frac{1+\frac{1}{x}}{3x + 2}$

3. Josiel

$\cfrac{2}{1+\cfrac{2}{1+\cfrac{2}{1+\cfrac{2}{1}}}}$

4. Luis lora

$/Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena • Josiel You mean$latex \Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena

• Josiel

Oh wait I mean

$\Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena$

5. Luis lora

$latex/Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena 6. Luis lora$latex/Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena$7. Gary $\int_{5}^{-3} x^3 + 5 dx$ • Kate Poirier Nice! If I were giving this question on a test, I’d probably put parentheses around the integrand to make it extra clear that the +5 is included: $\int_5^{-3} (x^3+5)dx$ 8. Luis lora $/Mu1=0=1=0=1=0=1=0=1=0=1=0=1/ngtr/Nu John Cena$ • Kate Poirier Close but it looks like your slashes are going the wrong way $\mu 1=0=1=0=1=0=1=0=1=0=1=0=1 \ngtr \nu John Cena$ • Kate Poirier I also changed your upper case Mu and Nu to lower case (the upper case ones are just M and N) 9. abdelmajid Here is a differential equation $2xsqrt(y)+xy^2=1$ • Kate Poirier Close! To get the square root symbol, don’t forget the backslash \sqrt instead of sqrt. (I know I said that it doesn’t matter if your math makes any sense, but I can’t stop myself from pointing out that this is not usually what we mean by “differential equation” because no derivatives appear in it. If $y$ is a function of $x$, then you could argue that $y$ is the zero-th derivative of itself, which would be correct, but it might make me roll my eyes.) • abdelmajid Agreed, I just noticed differential equation must have derivative in it, and my equation doesn’t have it . Actually when I wrote it I was focusing on the latex command more then the formula itself. • abdelmajid$latex\sqrt{y}2x+xy”=1 $• abdelmajid$ latex\sqrt{y}2x+xy”=1 $• Kate Poirier So close! Delete the space before “latex” and add a space after it; replace your double quotation with two single ones ‘ $\sqrt{y}2x+xy''=1$ • abdelmajid$ latex\sqrt{y}2x+xy”=1\$• abdelmajid$latex\sqrt{y}2x+xy”=1\$• abdelmajid$latex\sqrt{y}2x+xy”=1\ $• abdelmajid$latex\sqrt{y}2x+xy”=1\

• abdelmajid

$\sqrt{y}2x+xy”=1$

• abdelmajid

what a big mess I just created
one more last time
$Latex \sqrt{y}2x+xy”=1$

• Kate Poirier

Haha, now just make the L on “Latex” lower case, and you’re golden!

• abdelmajid

$\sqrt{y}2x+xy''=1$

• abdelmajid

$\sqrt[y]2x+xy”=1$

• abdelmajid

$\sqrt{y}2x+xy”=1$

10. Gary

$/sum_{n=1}^{\infty} 2^n/n (4x-8)^{n}$

• Kate Poirier

I bet you meant $\sum_{n=1}^{\infty}2^n(4x-8)^n$

11. Luis lora

$Latex setminus 12. Armando Cosme $\int_0^{2}\frac{x^2-4}{x-2}dx$ • Armando Cosme Wow, took a lot longer than expected -.- • Armando Cosme $\sqrt[3]{x^6 }$ • Kate Poirier Looks good! Once you get the hang of typing in Latex, it becomes much easier; the first attempts always take the longest…but practicing is the point of this exercise! 13. Evelin $\int_1^2 30(3x-4)^4dx$ • Kate Poirier Beautiful! 14. Evelin $(\sqrt{5x+6})^2=5x+6$ 15. Mei Zhu$latex/sqrt{x^2+1}+/sqrt[7]{x^3+5}$• Mei Zhu $\sqrt{x^2+1} + \sqrt[7]{x^3+5}$ • Kate Poirier Nice! 16. Tyniqua \intfrac{1}{arcsintheta}dx • Tyniqua$latex\intfrac{1}{arcsintheta}dx

• Tyniqua

$latex\intfrac{1}{arcsintheta}dx$

• Tyniqua

No luck for me.

• Tyniqua

$\intfrac{1}{arcsintheta}dx$

• Tyniqua

$latex\int\frac{1}{arcsintheta}dx$

• Tyniqua

$\int\frac{1}{arcsintheta}dx$

• Tyniqua

$\int\frac{1}{arcsin(theta)}dx$

• Tyniqua

$\int\frac{1}{arcsin\theta}dx$

• Kate Poirier

You got it eventually! Nice work!

It’s not important for this exercise, but I must point out that the variable in your integrand $\theta$ doesn’t match your variable of integration $x$, so if you were to evaluate your integral, your answer would just be $\frac{1}{\arcsin(\theta)}x +C$.

Just FYI, Latex knows the trigononometric (and inverse trigonometric) functions, so there is an \arcsin macro. It might not look like a big difference, but we typically prefer the roman characters to the italic ones:

$\int \frac{1}{\arcsin(\theta)} dx$ instead of $\int \frac{1}{arcsin(\theta)} dx$

17. Tyniqua

$latex\sqrt{9}$

• Tyniqua

$\sqrt{9}$

• Kate Poirier

There ya go!

18. Sonam

$latex/sqrt{x+3} 19. Sonam$latex /sqrt{5}/

20. Gary

$latex \sqrt{15}\ 21. Gary$latex \sqrt{6}/

22. Gary

$\sqrt{x^2+15}$

• Kate Poirier

Looks good!

23. Sonam

$\frac{x+1}{x^2 + 5x}$

• Kate Poirier

Lovely!

24. Sonam

$\sqrt{19}$

25. Sonam

$latex \sqrt{5} • Kate Poirier Close! Don’t forget to close up your Latex dollar signs: $\sqrt{5}$ 26. Josue$latex \sqrt{x^3 + / 1}

27. Josue

$\sqrt{x}$

28. Josue

$\sqrt{x^3 + / 1}$

• Kate Poirier

Nice! I’m not sure if you meant to have a fraction as a radicand. If so, you can use the Latex macro \frac:

$\sqrt{\frac{x^3+1}{1}}$

29. Bless

$\frac{x+1}{x^3+5x^2}$

• Kate Poirier

Great!

30. Bless

$\sqrt{x+1}+\sqrt[5]{x+6}$

31. Luis lora

$Latex (n^2-3n+4)/2$

32. Luis lora

$Latex /(n^2-3n+4)/2$

33. Luis lora

$latex (n^2-3n+4)/2$

34. Luis lora

$latex/(n^2-3n+4)/2 35. Luis lora$ latex/(n^2-3n+4)/2$• Kate Poirier So close! Move the space from before “latex” to after it. 36. Gary $/{n^2-3n+8}/2$ 37. Gary $(n^2-3n+8)/2$ 38. Armando Cosme $\ Two\ triangle's\ \triangle {ABC}\ and\ \triangle {A'B'C'}\ are\ perspective\ from\ a\ point\ if\ and\ only\ if\ they\ are\ perspective\ from\ a\ line.$ • Armando Cosme$latex\ \If \triangle ABC \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangleABC \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle.$• Armando Cosme$latex\ \If \triangle ABC \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangleABC \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle. $39. Armando Cosme$latex\ \If \triangle ABC \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangleABC \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle. $40. Armando Cosme$latex\ If \triangle ABC \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangleABC \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle.$• Armando Cosme$latex\ If \triangle{ABC} \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangle{ABC} \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle.$41. Armando Cosme$latex\ If \triangle {ABC} \ is \ any \ triangle, \ the \ three \ bisectors \ of \ the \ interior \ angles \ of \triangle {ABC} \ are \ concurrent. \ The \ point \ of \ concurrency \ is \ equidistant \ from \ the \ sides \ of \ the \ triangle.\$

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