Test # 2 Review

1 Comment

1. 

   Kate Poirier

   March 20, 2020 at 2:05 pm

   Hi Mamadou. I think you *can* use integration by parts here, but if your u = ln(x), then your dv = 1/x, not just x. Notice that if u = ln(x), then du = 1/x, so this is a good place to use u substitution. Also, don’t forget to keep your limits of integration throughout the process.

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