# Exam Review Number 1: Problem number 8

8.) The mean score on a Statistics exam was 82, with a standard deviation of 6. Find the standard score (z-score) for each of the students below.

• A.) Alice’s score was 94.

In order to find the Z score, we use the Z formula. This formula is:

Z equals X minus MU (mu is the same as the mean) divided by standard deviation.

We are given a mean score of 82 and a standard deviation of 6.

Our X is also given as Alice’s score of 94.

We now plug the numbers in and solve:

94-82/6

94-82=12

12/6=2

Alice’s Z score is: 2

• B.) Bob’s score was 76.

To find Bob’s Z score we use the Z formula as well.

Z equals X minus mu (mu is the same as the mean) divided by standard deviation.

Here our mean and standard deviation are the same but our X is different.

Our mean (which is given) is 82 and our standard deviation (also given) is 6.

Our X is Bob’s score which is 76.

Now we plug our numbers into the formula:

76-82/6

Here PEMDAS should also be used which means we subtract before we divide.

76-82=-6

-6/6=-1

• C.) Charlie’s score was 98.

To find Charlie’s Z score we use the Z formula as well.

Z equals X minus mu (mu is the same as the mean) divided by standard deviation.

Here our mean and standard deviation are the same but our X is different.

Our mean (which is given) is 82 and our standard deviation (also given) is 6.

Our X is Charlie’s score which is 98.

Now we plug our numbers into the formula:

98-82/6

Here PEMDAS should also be used which means we subtract before we divide.

98-82=16

16/6=2.67

Here is a picture of the work:
Hope this helps! 🙂

## 2 thoughts on “Exam Review Number 1: Problem number 8”

1. Sarina roche on said:

Can anyone explain number 9 on the revised review sheet?! Thanks.

Question: how many 5 digit zip codes can be made where all digits are unique? The possible digits are the numbers 0 through 9.

• Jonas Reitz on said:

Hi Holly,

If all the digits are unique, it means that once you’ve used a digit you can’t use it again. With this in mind, if we think about choosing 5 digits for our zip code, we have:
10 choices for the first digit (0,1,2,3,4,5,6,7,8,9)
only 9 choices for the second digit (because we can’t repeat the first digit)
only 8 choices for the third digit (because we can’t repeat the first digit or the second digit)
and so on.

The total number is therefore: 10*9*8*7*6