Resources: Final Exam review problem 5


This problem requires you to do arithmetic using complex numbers. It’s very much like ordinary algebra, except that you must remember that i^{2} = -1, and also to put your final. answer into the standard (“rectangular”) form a + bi.

Also remember, since i is a radical (it’s \sqrt{-1}), we divide by rationalizing the denominator, which means we have to multiply top and bottom by the conjugate of the denominator. It is helpful to remember that (a+bi)(a-bi)=a^{2} + b^{2}.


WeBWorK on ComplexNumbers (Use “Show Me Another” if you have already completed this)

Video showing a solution of #5d


Leave a Reply