Xn = Xn-1 + (1 + n)
X0 = 3
X1 = 3 + (1 + 1) = 5
X2 = 5 + (1 + 2) = 8
X3 = 8 + (1 + 3) = 12
Professor Kate Poirier, Spring 2017
Xn = Xn-1 + (1 + n)
X0 = 3
X1 = 3 + (1 + 1) = 5
X2 = 5 + (1 + 2) = 8
X3 = 8 + (1 + 3) = 12
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