Month: December 2019 (Page 1 of 4)

Final Exam Review – Questions

Jacky’s Exams Solutions

Final Exam Review

These are the solutions for test I made.

    

step3,

Final Exam Review sheet-Questions

  

step2, from DECEMBER 14, 2019 / IQRA ，finalexamreviewquestions

 

You can see videos of worked solutions here.  I recommend you don’t watch the video for a particular question until you’ve already spent at least 20 minutes trying to answer the question on your own.

Marcus Final exam review solutions

1a)(sqrt(6)+sqrt(2))/2

1b)-(sqrt(2)+sqrt(6))/4

2a) magnitude=sqrt(10)

angle=79.1 degrees

2b) magnitude=1.479

angle=115.84

3a){x=3}

3b){x=6}

4a)domain:(0, inf)

4b)domain:(-7, inf)

4c)domain:(-5, inf)

5a)domain:(-inf,2)U(2,4)U(4,inf)

vertical:(2,0)&(4,0)

removal:none

5b)domain:(-inf,-2)U(-2,0)U(0,2)

vertical:(0,0)&(-2,0)

removal:(2,0)

6a)(3+4i)

6b)(-14+2i)

7a)(x^2-2x-2-3/(x-2))

7b)(x^2+3x-2+4/(x+3))

8a)all real roots:1/2, 2/3,…

8b)all real roots:-1/4

9a)(pi-pi/4)+2*pi*n

9b) pi/4+2*pi*n

9c) pi/6+2*pi*n

10a)magnitude=sqrt(100) ,  angle=53.1

10b)magnitude=111.8, angle=sqrt(29)

10c) magnitude=225, angle=4*sqrt(2)

 

Jayvon Final exam Question solutions

1a) 3^5x+2=9^x+4

3^5x+2=3^2x+8

5x+2=2x+8

5x=2x+6

3x=6

x=2

1b) 5^x+3=7^x

ln5^x+3=ln7^x

(x+3)*ln5=x*ln7

x*ln5+3*ln5=x*ln7

xln5-xln7=3ln7

x(ln5-ln7)=3ln7

x=3ln5/(ln5-ln7)

2a) x^2-2x-3>=0

x^2-2x-3>=0

(x+1)=0  &.  (x-3)=0

x=-1  &    x=3

x>=-1    &    x>=3

(-inf,-1)U(3, inf)

2b) |x-4| >= 7

(x-4)>=7    &    -x+4>=7

x>=11      &      x=<-3

(-inf, -3) U (12, inf)

3) y=2*sin(4x-pi)

amplitude:2

period:1/2pi

phase shift:pi/4

minima:-2

maxima:2

pi/4+2*pi*n

4a) y=5+6x

x=5+6y

f^-1(x)=(x-5)/6

4b) y=2/(8x+5)

x=2/(8y+5)

f^-1(x)=(2/x-5)/8

5) f(x)=(x+2)/(3-x)

x-int:2

y-int:2/3

domain:(-inf, 3)U(3, inf)

vertical:3

horizontal:-2

6a) 3(cos315+I*sin315)/18(cos135+I*sin135)

3/18* cos(315-135)+I*sin(315-135)

1/6*cos(180)+I*sin(180)

1/6*(-1+0i)

-1/6

6b) ln* sqrt(x^3*4*sqrt(y))

ln x^3^1/2+ln y^1/4^1/2

sqrt(3)u+1/2v

7)a. a1:5

b. ratio:5

c. a_n*r^n-1=5*5^n-1

d. 5^n*5^10-1=9765625

8)2015-2003=12

80,000(1+.04)^13

=133205

3=(1+.04)^x

(ln3/ln1.04=x)

9a) sqrt((-5sqrt(3))^2+(5)^2)

sqrt(100)=10

magnitude=10

tan^-1(5/-5*sqrt(3))

tan^-1(5/-5*sqrt(3))=-30+180=

angle=(150 degrees)

10)sin(2a)=(-14*sqrt(113))/16)

cos(2a)=(-1)

tan(2a)=(sqrt(113)/-32)