# MAT1375 Precalculus Fall 2019

Fall 2018 | Professor Kate Poirier

You can see videos of worked solutions here.  I recommend you don’t watch the video for a particular question until you’ve already spent at least 20 minutes trying to answer the question on your own.

The instructions for your Test #3 Solutions OpenLab assignment are the same as for Test #1 and Test #2 solutions. Your post is due by Thursday, December 12 at 11:59pm. Don’t forget to select the category Test #3 Solutions before publishing your post.

Your Final Exam Review OpenLab assignment has three steps:

1. Create your own final exam. Refer to questions from the final exam review sheet, WeBWorK, quizzes, tests, and the textbook to put together an exam that reflects all the topics you saw in this course. Your exam should have ten questions (but many questions should have a part (a) and a part (b) so your exam will have up to 20 questions). Don’t worry about whether you can answer the questions yourself; try to select good exam questions. Submit your final exam as an OpenLab post with the Subject Final Exam Review and the category Final Exam Review – Questions.
2. Take one of your classmates’ final exams. Set aside 100 minutes and take the exam as though it were actually the final exam: turn your phone off and leave your notes, etc, in another room. After time is up, make a note of which questions you struggled with (you will need to spend more time studying these topics); figure out the solutions to these problems. Make a good copy of your solution sheet and post this on the OpenLab. Link to your classmate’s OpenLab post with the questions in your post and select the category Final Exam Review – Solutions.
3. Repeat step 2 but with your own final exam.

Due dates:

Step 1: Final exam questions are due by Friday, December 13 at 11:59pm

Steps 2 & 3: Final exam solutions are due by Monday, December 16 at 11:59pm

Bonus (optional): Grade somebody else’s final exam. Submit your questions/concerns as a comment on their Solutions post. Submit these by Wednesday, December 17 at 11:59pm.

Steps 1, 2, and 3 (and the optional bonus step) are each worth one participation point.

Final Exam Review – Questions

Jacky’s Exams Solutions   Final Exam Review

These are the solutions for test I made.    Marcus Final exam review solutions

1a)(sqrt(6)+sqrt(2))/2

1b)-(sqrt(2)+sqrt(6))/4

2a) magnitude=sqrt(10)

angle=79.1 degrees

2b) magnitude=1.479

angle=115.84

3a){x=3}

3b){x=6}

4a)domain:(0, inf)

4b)domain:(-7, inf)

4c)domain:(-5, inf)

5a)domain:(-inf,2)U(2,4)U(4,inf)

vertical:(2,0)&(4,0)

removal:none

5b)domain:(-inf,-2)U(-2,0)U(0,2)

vertical:(0,0)&(-2,0)

removal:(2,0)

6a)(3+4i)

6b)(-14+2i)

7a)(x^2-2x-2-3/(x-2))

7b)(x^2+3x-2+4/(x+3))

8a)all real roots:1/2, 2/3,…

8b)all real roots:-1/4

9a)(pi-pi/4)+2*pi*n

9b) pi/4+2*pi*n

9c) pi/6+2*pi*n

10a)magnitude=sqrt(100) ,  angle=53.1

10b)magnitude=111.8, angle=sqrt(29)

10c) magnitude=225, angle=4*sqrt(2)

Jayvon Final exam Question solutions

1a) 3^5x+2=9^x+4

3^5x+2=3^2x+8

5x+2=2x+8

5x=2x+6

3x=6

x=2

1b) 5^x+3=7^x

ln5^x+3=ln7^x

(x+3)*ln5=x*ln7

x*ln5+3*ln5=x*ln7

xln5-xln7=3ln7

x(ln5-ln7)=3ln7

x=3ln5/(ln5-ln7)

2a) x^2-2x-3>=0

x^2-2x-3>=0

(x+1)=0  &.  (x-3)=0

x=-1  &    x=3

x>=-1    &    x>=3

(-inf,-1)U(3, inf)

2b) |x-4| >= 7

(x-4)>=7    &    -x+4>=7

x>=11      &      x=<-3

(-inf, -3) U (12, inf)

3) y=2*sin(4x-pi)

amplitude:2

period:1/2pi

phase shift:pi/4

minima:-2

maxima:2

pi/4+2*pi*n

4a) y=5+6x

x=5+6y

f^-1(x)=(x-5)/6

4b) y=2/(8x+5)

x=2/(8y+5)

f^-1(x)=(2/x-5)/8

5) f(x)=(x+2)/(3-x)

x-int:2

y-int:2/3

domain:(-inf, 3)U(3, inf)

vertical:3

horizontal:-2

6a) 3(cos315+I*sin315)/18(cos135+I*sin135)

3/18* cos(315-135)+I*sin(315-135)

1/6*cos(180)+I*sin(180)

1/6*(-1+0i)

-1/6

6b) ln* sqrt(x^3*4*sqrt(y))

ln x^3^1/2+ln y^1/4^1/2

sqrt(3)u+1/2v

7)a. a1:5

b. ratio:5

c. a_n*r^n-1=5*5^n-1

d. 5^n*5^10-1=9765625

8)2015-2003=12

80,000(1+.04)^13

=133205

3=(1+.04)^x

(ln3/ln1.04=x)

9a) sqrt((-5sqrt(3))^2+(5)^2)

sqrt(100)=10

magnitude=10

tan^-1(5/-5*sqrt(3))

tan^-1(5/-5*sqrt(3))=-30+180=

angle=(150 degrees)

10)sin(2a)=(-14*sqrt(113))/16)

cos(2a)=(-1)

tan(2a)=(sqrt(113)/-32)

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