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- How the two derived identities help prove that the 2-basis ensures $\mathtt{NAND}$'s functional completeness? May 10, 2025I am proving that $\mathtt{NAND}$ is functionally complete in Boolean algebra using Robert Veroff’s 2-basis for the Sheffer stroke ($\mathtt{NAND}$) from his paper (A Shortest 2-Basis for Boolean Algebra in Terms of the Sheffer Stroke). I need clarification on how two derived identities from the paper’s proof contribute to constructing the standard $\mathtt{NAND}$ expressions for […]Dang Dang
- What is meant by this statement of Lavwere about the arrow category? May 8, 2025I am reading the thesis, Functorial Semantics of Algebraic Theories by Lawvere. Starting on page 26, he describes the category of categories, with functors as morphisms. He describes some special objects in this category, which he names 0, 1 and 2. The first two are what you expect, and 2 is the arrow category, consisting […]Carlyle
- Is there a "true" value of BB(745)? May 7, 2025I was reading this reddit thread and I got confused by one part. I always thought that there is always a "true" value of BB(n), even though it might not be provable or findable. There is a 745-state Turing Machine that halts iff ZFC is inconsistent. By Gödel's second incompleteness theorem, ZFC cannot prove BB(745) […]David Lui
- Is it necessary the existence of a set to prove the existence of empty set? [duplicate] May 6, 2025I know that in a set theory like Z or ZF we can prove the existence of the empty set starting from the existence of any set (guaranteed for example from infinity axiom) using the separation axiom on the first order formula $x\neq x$. However, it seems to me that it is not really necessary […]Manuel Bonanno
- Toposes as a generalization of the notion of groups [closed] May 6, 2025While listening to an introductory lecture on topoi (or toposes ;)) I was surprised when the lecturer said that toposes could be seen as a generalization of the notion of groups. I don’t know to what it refers and have had a hard time finding any source about this. Is it something you heard about, […]Iq-n-dI
- Does cut elimination imply invertability in some cases? May 6, 2025I am currently reading a paper presenting a (Gentzen-style) proof system without a cut rule. In it, cut elimination is proven first, so if $\phi \sqsubseteq \psi$ and $\psi \sqsubseteq \rho$ have proofs, then $\phi \sqsubseteq \rho$ does as well. In Theorem 4.1, he then claims that if $\phi \sqsubseteq \psi_1 \sqcap \psi_2$ has a […]Snek
- Given $\phi(\overline{x})$ a non-algebraic formula, there exists an indiscernible sequence $(a_i)_{i<\lambda}$ such that $\phi(a_{i_1},...,a_{i_n})$ [closed] May 6, 2025Let $\phi(\overline{x})$ be a non-algebraic formula (we may suppose over the emptyset). There exists an indiscernible sequence $(a_i)_{iMoreno Invitti
- Does Godel's incompleteness really means that parsability of language entails ill-self-reference? May 6, 2025I want to make the following claim. Could you please correct me, thanks ? Godel's incompleteness theorem relies on the folding of higher order structure with the arithmetic one, leading to self reference which states impossible "liar sentences". This is due to the parsability of the sentences of FOL and its tree data structure. An […]Ok Ok
- What is the basis for assuming $V \neq L$? May 6, 2025My understanding is that Godel proved if $ZFC$ is consistent, then $ZFC + (V=L)$ is also consistent. But what about the negation, i.e. $V \neq L$? Is it similarly provable that if $ZFC$ is consistent then $ZFC + (V \neq L)$ is also consistent? Or is $V \neq L$ effectively an axiom that has to […]NikS
- Using the construction in Kleene's recursion theorem to build a quine May 4, 2025Kleene's recursion theorem guarantees that, for every computable function $f$, there is a program $e$ such that $e$ and $f(e)$ compute the same function, or equivalently, $\varphi_e(x) \simeq \varphi_{f(e)}(x)$. The theorem is proven constructively as follows. Let $S$ be the computable function such that $\varphi_{S(k, p)}(x) = \varphi_p(k, x)$. Let $$\varphi_{f(S(u, u))}(x) =: g(u, x)$$ […]lafinur
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