Good evening all! Since test #1 is coming up on next Thursday (10/8/2020), it is important to review all of the integration techniques we have learned so far. Integration by substitution is one of them!
I have decided to do problems #9 and #14 in the Integration by Substitution homework set in WeBWorK. This post will be updated over time based on feedback I receive.
Contents
Problem #9
- This is a problem of moderate difficulty. You have to evaluate the indefinite integral.
- Find u: (u =x6 + 5; du = x5 dx).
- Perform u-substitution. Note that x5 has been divided, so it has been turned to 1/6 according to the power rule.
- Use the natural log rule.
- Put the original value (x6 + 5) back in place of u.
Problem #14
- This is a problem of harder difficulty, with multiple steps. You have to evaluate the definite integral, and find out if the integral is defined or not.
- Find u: (u = 3x – 4; du = 3 dx). You should divide 3 by both sides in order for du to fit the form of dx.
- Perform u-substitution.
- Use the constant multiple rule for 1/3 and 5. (Hint: 5 × 1/3)
- Use the power rule for u-23.
- Simplify by multiplying.
- Put the original value (3x-4) back in place of u.
- Evaluate the integral. Remember that the upper bounds are 8/3 (or 2 ⅔), and lower bounds are 0. Then, simplify accordingly based on the values you substituted in their respective places.
Note: Since 422 is an extremely large number, I have to round this number to three significant figures (1.76 × 1013), and use scientific notation in this case.
With enough simplification, you will notice that the denominators are alike, and you can now combine -5 and +5.
Therefore, the definite integral is 0.
Motivating questions
- In problem #9, in Step 3, how did I turn x5 to 1/6 before performing u-substitution?
- In problem #14, WeBWorK’s answer is “The integral does not exist”, but I wrote that the integral is 0. What are the possible errors I have made in my step-by-step procedure?
Leave a Reply