- (1 point) solve -x^2-3x <= -10
2) First solve by adding +10 to both sides of the inequality
-x^2-3x+10<=0
3) Then you need to factor out -1 in the the inequality to make the leading coefficient positive.
-1(x^2+3x-10)<=0
4) After that you need to factor the inequality of what can multiply into -10 and add up to +3
-1(x+5)(x-2)<=0
5) Then you need to set them both equal to zero and place -1 in front of both of them
-1(x+5)=0 and -1(x-2)=0
6) Once you do that then factor in the -1
-x-5=0 and -x+2=0
7) Then solve for x
x=-5 and x=2
8) Make sure to switch the inequality
x>=-5 and x>=2
9) Write your answer in interval notation
Answer=(-inf, -5] U [2, inf)
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