1. (1 point) solve  -x^2-3x <= -10

2) First solve by adding +10 to both sides of the inequality

-x^2-3x+10<=0

3) Then you need to factor out -1 in the the inequality to make the leading coefficient positive.

-1(x^2+3x-10)<=0

4) After that you need to factor the inequality of what can multiply into -10 and add up to +3

-1(x+5)(x-2)<=0

5) Then you need to set them both equal to zero and place -1 in front of both of them

-1(x+5)=0 and -1(x-2)=0

6) Once you do that then factor in the -1

-x-5=0 and -x+2=0

7)  Then solve for x

x=-5 and x=2

8) Make sure to switch the inequality

x>=-5 and x>=2

9) Write your answer in interval notation

Answer=(-inf, -5] U [2, inf)