EX10 11/1/2018

2 Responses to EX10 11/1/2018

1. Joel Sanchez says:

   November 1, 2018 at 7:42 pm

   %%JOEL SANCHEZ
   %% CLASSWORK EX10 11/1/2018
   %%1.)
   %Solve for T1 T2 T3
   %T1+T2+T3 -400 = 0
   %1600-10*T2-5*T3=0
   A=[1,1,1;0,-10,-5];
   B=[400;-1600];
   C=A\B
   %%2.)
   % SOLVE FOR x y z
   %12x-5y=11
   %-3x+4y+7z=-3
   %6x+2y+3z=22
   A=[12,-5,0;-3,4,7;6,2,3];
   B=[11;-3;22];
   C=A\B
   %%3.)
   %Solve for T1 T2 T3
   A=[(1/sqrt(35)),(-3/sqrt(34)),(1/sqrt(42));(3/sqrt(35)),(0),(-4/sqrt(42));(5/sqrt(35)),(5/sqrt(34)),(3/sqrt(42))];
   B=[0;0;1];
   C=A\B

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2. David Le says:

   November 1, 2018 at 7:43 pm

   %% David Le

   % 1.
   % Solve T1, T2, T3
   % T1+T2+T3 -400 = 0
   % 1600-10*T2-5*T3=0

   A = [1 1 1;0 -10 -5];
   B = [400;-1600];
   C = A\B

   % 2.
   % Solve x, y, z
   % 12x-5y=11
   % -3x+4y+7z=-3
   % 6x+2y+3z=22

   A = [12 -5 0;-3 4 7;6 2 3];
   B = [11;-3;22];
   C = A\B

   % 3.
   % Solve T1, T2, T3
   % (T1/sqrt(35))-(3*T2/sqrt(34))-(T3/sqrt(42))=0
   % (3*T1/sqrt(35))-(4*T3/sqrt(42))=0
   % (5*T1/sqrt(35))-(5*T2/sqrt(34))-(3*T3/sqrt(42))-mg=0
   % mg = 1

   A = [(1/sqrt(35)),(-3/sqrt(34)),(1/sqrt(42));(3/sqrt(35)),(0/sqrt(34)),(-4/sqrt(42));(5/sqrt(35)),(5/sqrt(34)),(3/sqrt(42))];
   B = [0;0;1];
   C = A\B

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