Statistics with Probability

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  • #12927

    Afzal
    Participant

    professor can you do nu-1 and 2 from Q-9. i think number 1 we already did in our first exam and non of the review problems match with problem-1 from Q-9.

    #16011

    Ezra Halleck
    Participant

    You are right. I had mixed feeling about Q9 since part of it wasn’t going to be on the 2nd exam. But here goes:
    1. P(X=0)=34nCr2/40nCr2, P(X=1)=6nCr1*34nCr1/40nCr2, P(X=2)=6nCr2/40nCr2

    2. The outcomes are YY, YN, NY and NN with probabilities .5*.6,.5*.4,.5*.4,.5*.6 pr .3,.2,.2 and .3 respectively. As a random variable (number of baskets) P(X=0)=.3, P(X=1)=.4, P(X=2)=.3 so expectation is .4+2*.3= 1

    3. P(X=4)=1-(.1+.3+.4)=.2
    x 1 2 3 4
    P(x) 0.1 0.3 0.4 0.2
    E[X]=.1+.6+1.2+.8=2.7

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