Warmup Questions II

These are questions on fundamental concepts that you need to know before you can embark on this lesson. Don’t skip them! Take your time to do them, and check your answer by clicking on the “Show Answer” tab.

Warmup Question 5

Simplify $$\sqrt{72}.$$

Show Answer 5

$$\sqrt{72}=\sqrt{36\cdot 2} = \sqrt{36}\sqrt{2} = 6\sqrt 2$$

Warmup Question 6

Solve by completing the square.

$$x^2+bx+c=0$$

Show Answer 6

$$x^2+bx+c =0$$

$$x^2+bx=-c$$

$$x^2+bx+\dfrac{b^2}{4} = -c+\dfrac{b^2}{4}$$

$$\left(x+\dfrac{b}{2}\right)^2 = \dfrac{b^2-4c}{4}$$

$$x+\dfrac{b}{2} =\pm\sqrt{\dfrac{b^2-4c}{4}}$$

$$x =- \dfrac{b}{2}\pm\dfrac{\sqrt{b^2-4c}}{2}$$

$$x= \dfrac{-b\pm\sqrt{b^2-4c}}{2}$$

The solution set is $\left\{\dfrac{-b-\sqrt{b^2-4c}}{2},\dfrac{-b+\sqrt{b^2-4c}}{2}\right\}$.

Quick Intro II

This is like a mini-lesson with an overview of the main objects of study. It will often contain a list of key words, definitions and properties – all that is new in this lesson. We will use this opportunity to make connections with other concepts. It can be also used as a review of the lesson.

A Quick Intro to the Quadratic Formula

Key Words. Coefficient, standard form, quadratic formula.

Consider

$$ax^2+bx+c=0.$$

In the Video Lesson 1, we saw that if we complete the square and use the Square Root Property, we obtain that

$$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}.$$

This is the Quadratic Formula. It depends on $a$, $b$ and $c$, which are the coefficients of the quadratic polynomial $ax^2+bx+c$. The first step in using the quadratic formula is to make sure that the polynomial is set to be zero. This is called the standard form.

$$-5x^2=-3x\quad\text{is not in standard form.}$$

$$x^2+3x-5=0\quad\text{is in standard form.}$$

In this case, $a=1$, $b=3$ and $c=-5$.

Video Lesson II

Many times the mini-lesson will not be enough for you to start working on the problems. You need to see someone explaining the material to you. In the video you will find a variety of examples, solved step-by-step – starting from a simple one to a more complex one. Feel free to play them as many times as you need. Pause, rewind, replay, stop… follow your pace!

Video Lesson 2

A video lesson on the Quadratic Formula [9:38]

A description of the video

In the video you will see how to solve the following equations by using the quadratic formula.

  • $2x^2-5x-3=0$
  • $4x^2-8x+1=0$
  • $x(4x-3)=11+x$
  • $x^2+2x+5=0$

Try Questions II

Now that you have read the material and watched the video, it is your turn to put in practice what you have learned. We encourage you to try the Try Questions on your own. When you are done, click on the “Show answer” tab to see if you got the correct answer.

Try Question 9

Solve $2x^2+4=-4x$ by using the quadratic formula.

Show Answer 9

The equation written in standard form is $2x^2+4x+4=0$.  Let’s divide both sides by $2$.  We get

$x^2 + 2x +2 =0$.  So $a=1$, $b=2$ and $c=2$.  The quadratic formula gives

$$x =\dfrac{-b\pm \sqrt{b^2-4ac}}{2a} = \dfrac{-2\pm \sqrt{2^2-4\cdot 1 \cdot 2}}{2\cdot 1} $$

$$=\dfrac{-2\pm \sqrt{-4}}{2} = \dfrac{-2\pm \sqrt{4}i}{2} = \dfrac{-2\pm 2i}{2} $$

$$= \dfrac{-2}{2}\pm \dfrac{2i}{2} = -1\pm i$$

The solution set is $\{-1+ i,-1-i\}$.

WeBWorK II

You should now be ready to start working on the WeBWorK problems. Doing the homework is an essential part of learning. It will help you practice the lesson and reinforce your knowledge.

WeBWorK II

It is time to do the homework on WeBWork:

QuadraticFormula

When you are done, come back to this page for the Exit Questions.

Exit Questions II

After doing the WeBWorK problems, come back to this page. The Exit Questions include vocabulary checking and conceptual questions. Knowing the vocabulary accurately is important for us to communicate. You will also find one last problem. All these questions will give you an idea as to whether or not you have mastered the material. Remember: the “Show Answer” tab is there for you to check your work!

Exit Questions

  • How is the quadratic formula related to the process of completing the square? 
  • Why would we ever need or want to factor if we have the quadratic formula? 
  • Suppose we use the quadratic formula to solve a quadratic equation, what does what is under the radical symbol tell us about the solution(s) ?

$\bigstar$ Solve $2x^2+4=-4x$ by using the quadratic formula.

Show Answer

The equation written in standard form is $2x^2+4x+4=0$.  Let’s divide both sides by $2$.  We get $x^2 + 2x +2 =0$.  So $a=1$, $b=2$ and $c=2$.  The quadratic formula gives

$$x =\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$$

$$x = \dfrac{-2\pm \sqrt{2^2-4\cdot 1 \cdot 2}}{2\cdot 1} $$

$$x= \dfrac{-2\pm \sqrt{-4}}{2}$$

$$x = \dfrac{-2\pm \sqrt{4}i}{2} $$

$$x= \dfrac{-2\pm 2i}{2} $$

$$x= \dfrac{-2}{2}\pm \dfrac{2i}{2} = -1\pm i$$

The solution set is $\{-1+ i,-1-i\}$.