Calculus I

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  • April 2, 2013 at 2:41 am #13233

    Ezra Halleck
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    Find the derivative a rather complicated function (2 intricate compositions of inverse trig and power functions, and an exponential function).

    April 12, 2013 at 8:12 pm #16814

    Danielle Telemaque
    Participant

    y = [ (tan ^(-1))(x^2-1) ]^3 + sin^(-1)2x +(1/3)^(1-x)

    = 3 [ tan ^(-1) *(x^2-1) ]^2 * (2x/(1+(x^2-1)^2) + (2/((1-(2x)^2)^(1/2)) + 3^(x-1)/ln(3)

    = ((6 [tan^(-1) (x^2-1) ]^2/ (1+ (x^2-1))^2) + ((2)/(1-4x^2)^(1/2) + (ln(3)/ 3^(1-x))

    Answer is A

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