Fall 2016 - Professor Kate Poirier

Extended Law of Sines

  1. If \triangle{ABC} is a triangle with circumradius R, then

\frac{BC}{sin(\angle{BAC})}=\frac{AC}{sin(\angle{ABC})}=\frac{AB}{sin(\angle{ACB})}=2R

2.  https://www.geogebra.org/m/mHCYrmXy

3 Comments

  1. Armando Cosme

    Hey Evelin,
    Your link isn’t quite working for me, do you mind posting another?

    Thank You

    • Mei Zhu

      I found the same problem.

  2. Evelin

    https://ggbm.at/mHCYrmXy

    Here’s the link to my dynamic worksheet. Sorry for that guys.

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