Contents

## Video

(click the link to view video)

https://www.dropbox.com/s/zz4kf2w0p2j8mzh/Enriquez_MAT2680_Project_3.MOV?dl=0

## Steps

Use “Undetermined coefficients” method

1. Solve for the roots of the characteristic equation.
2. Find a suitable general form for a “particular solution”, , that matches the “right side of the given equation” ( is the same as , which is function representing the amount of charge of a sytem).
• if the right side of the equation is , , or , then the particular solution is of the form • since no terms in is a solution of the complimentary equation, no extra steps are necessary in deciding the form of the particular solution
3. Differentiate the chosen particular solution twice to find and .
4. Substitute the values of , , and into , , and .
8. Plug in the values of the undetermined coefficients into the chosen particular solution to determine .
9. Since the steady steady state current, , is equal to , we must differentiate to solve for the steady state current of the system.