Notes: The group correctly identified that a non-zero determinant for the coefficient matrix implies a unique solution. And finding the value x = -5 using Cramer’s rule
Problem 2
Score:
Notes: The components of the vector PQ were correctly calculated by subtracting P from Q to get <-4, -2, 1>. The norm ||PQ|| =√21 and the resulting unit vector u were both derived accurately.
Problem 3
Score:
Notes: The group has the right idea regarding vector addition and navigation through the diagram. For example, part (e) correctly demonstrates the tip-to-tail method: AB +BC – OC= AC+ CO = -u – v.
Problem 4
Score:
Notes: The solution is perfect and exhaustive. The group correctly calculated:
The dot product is 6.
The vector projection projv (u) = <18/35, -6/35, 30/35>
The cross product u x v = <4,-23,-7>
The angle ፀ≈76.17°
Verification that the cross product is orthogonal to the original vectors
Problem 5
Score:
Notes: The work is perfectly executed. The group established the correct parametric equation for the line and then accurately checked if the point (-11, -8, -1) existed on that line by solving for the parameter $t$. They correctly found that t = -2 consistently satisfies all three coordinate equations.
Problem 6
Score:
Notes: The group correctly answered the conceptual True/False questions and provided valid examples for (b) and (e), counterexamples for (a), (c), and (d)
Problem 7
Score:
Notes: All examples provided are correct and demonstrate a clear understanding of the concepts. The group successfully found a point Q for a given vector, provided two orthogonal vectors with a zero dot product, and correctly constructed a unit vector that was not a standard basis vector.
Problem 1
Score:
Notes: The group correctly identified that a non-zero determinant for the coefficient matrix implies a unique solution. And finding the value x = -5 using Cramer’s rule
Problem 2
Score:
Notes: The components of the vector PQ were correctly calculated by subtracting P from Q to get <-4, -2, 1>. The norm ||PQ|| =√21 and the resulting unit vector u were both derived accurately.
Problem 3
Score:
Notes: The group has the right idea regarding vector addition and navigation through the diagram. For example, part (e) correctly demonstrates the tip-to-tail method: AB +BC – OC= AC+ CO = -u – v.
Problem 4
Score:
Notes: The solution is perfect and exhaustive. The group correctly calculated:
Problem 5
Score:
Notes: The work is perfectly executed. The group established the correct parametric equation for the line and then accurately checked if the point (-11, -8, -1) existed on that line by solving for the parameter $t$. They correctly found that t = -2 consistently satisfies all three coordinate equations.
Problem 6
Score:
Notes: The group correctly answered the conceptual True/False questions and provided valid examples for (b) and (e), counterexamples for (a), (c), and (d)
Problem 7
Score:
Notes: All examples provided are correct and demonstrate a clear understanding of the concepts. The group successfully found a point Q for a given vector, provided two orthogonal vectors with a zero dot product, and correctly constructed a unit vector that was not a standard basis vector.
Idk why the stars are so big, but all of them are solutions are correct
Haha enormous stars are great!
Group Member: AHR, SL, CT, SCC