# My Question(s)

Fairly easily. I can surely say we can all agree we don’t want any hard questions. (PS: I have no idea how to use laTeX, so I hope you guys can understand my fail attempt to write a math problem online.)

1) The limit below represents the derivative of f ‘(a). Find the f(x) and the a values.

Lim h->0 of ((3+h)^3) – 27)/h

f(x) = ?

a = ?

2) Find the slope of the secant line through the points of x = 2 and x=4 of the function f(x) = x^2. ( Not sure if I typed this correctly I was half asleep when I woke up: Correct me If I’m wrong)

Slope= ?

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### 4 Responses to My Question(s)

1. Masaab Sohaib says:

1)
$\frac{(3+x)^3-27}{x}$
$\downarrow$
$\lim_{x\to}$ $\frac{(3+x)^3-(3^3)}{x}$
$\downarrow$
$f(x)=x^3$
So,
$/frac{d}{dx}$ $f(x)=3x^2$

• Masaab Sohaib says:

$\frac{d}{dx}$ $f(x)=3x^2$

2. Masaab Sohaib says:

2)
$f(x)=x^2$
$f(2)=2^2 = 4$
&latex f(4)=4^2 = 16\$
so,
$\downarrow$
(2, 4) , (4, 16)
$\downarrow$
$m=\frac{detlaY}{deltaX}$
$m=\frac{16-4}{4-2}$
$m=6$
$\downarrow$
$y-y1 = m(x-x1)$
$y-4 = 6(x-2)$
$y= 6x-8)$

• Masaab Sohaib says:

$f(4)=4^2 = 16$

Sorry, Still trying to learn this latex 🙂