My Question(s)

Posted on March 7, 2014 by Darren

Fairly easily. I can surely say we can all agree we don’t want any hard questions. (PS: I have no idea how to use laTeX, so I hope you guys can understand my fail attempt to write a math problem online.)

1) The limit below represents the derivative of f ‘(a). Find the f(x) and the a values.

Lim h->0 of ((3+h)^3) – 27)/h

f(x) = ?

a = ?

2) Find the slope of the secant line through the points of x = 2 and x=4 of the function f(x) = x^2. ( Not sure if I typed this correctly I was half asleep when I woke up: Correct me If I’m wrong)

Slope= ?

 

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4 Responses to My Question(s)

  1. Masaab Sohaib says:
    March 7, 2014 at 3:26 pm

    1)
    \frac{(3+x)^3-27}{x}
    \downarrow
    \lim_{x\to} \frac{(3+x)^3-(3^3)}{x}
    \downarrow
    f(x)=x^3
    So,
    /frac{d}{dx} f(x)=3x^2

  2. Masaab Sohaib says:
    March 7, 2014 at 3:53 pm

    2)
    f(x)=x^2
    f(2)=2^2 = 4
    &latex f(4)=4^2 = 16$
    so,
    \downarrow
    (2, 4) , (4, 16)
    \downarrow
    m=\frac{detlaY}{deltaX}
    m=\frac{16-4}{4-2}
    m=6
    \downarrow
    y-y1 = m(x-x1)
    y-4 = 6(x-2)
    y= 6x-8)

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