Test # 2 Problem 2

1 Comment

1. 

   Opemipo Odugbemi

   April 24, 2023 at 10:41 pm

   I had a very similar question mine was y” + 6y’ + 45y = 0

   I did the characteristics equation;

   my fundamental roots came out to be -3 +or- 6i which brings us to case 3

   where we have the real part and and imaginary.

   Y1 = e^-3x Cos(6x) Y2 = e^-3x sin(6x)

   My general solution came out to be;

   y = e^-3x Cos(6x) + e^-3x sin(6x)

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