MAT2680 Differential Equations, FA2013

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    Keven Deng
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    Hello professor I’ am a little bit confused on the slide 23 for powerpoint 2.4 where the standard form equation v’-(7/t)v=-3/t^2 becomes (v*t^-7)=-3t^-9. The thing I want to ask about is how does -3/t^2 convert to -3t^-9. In addition for v’-(7/t)v it becomes (v*t^-7)’ by inverse of the product rule but when I take the derivative of (v*t^-7)’ I get v'(t^-7)-v(7t^-8) which doesn’t match up to v’-(7/t)v.

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