# Mat 1475

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• #42042

Group members: Tanvir Ahmed
Brian Uelasco
Harsimarsit Singh
Moneoul Islam
Melvin Laurent

Note: In this topic we will discuss about what we did for the hiker problem and share what answers we came up for it.

#42043

1. (a) The tangent line is a straight line that touches a function at one point and because we are talking about hiking on a mountain, the tangent line will give us an indication of how high our hiker has traveled and thus, show us the difficulty of the hike.
(b) The slope of the tangent line is pretty small
(c)For this part I used differentiation
e(x)=125x^2-6.25x^3
125*(2)x-6.25*(3)x^2
e'(x)=250x-18.75x^2 (In miles)
(d) For this part I used the derivative to find the place it equals to zero or the place it reaches the highest point
0=250x-18.75x^2
0=x(250-18.75x)
0/x=x(250-18.75x)/x
0=250-18.75x
-250=-18.75x
x=13 1/3 or 13.33333333333333 miles
(e) Using what we got in (d), we can now get the highest point on the trail by using the original equation
e(x)=125x^2-6.25x^3
=125(13.33333333333333)^2-6.25(13.33333333333333)^3
=7407.407407

#42046

Sorry i couldn’t reply earlier and i wished i could have helped in the problem but uhh this is Tanvir- my email and number is kaidaxts@gmail.com 3474752651. feel free to contact me when you want to. Regarding this question, ive done part a and b and got the same answer, part c-e got stuck on but just saw your response and it makes sense to me lol.

#42119

sorry I’m late but I pretty much got the whole question but part e correct. by looking at the way you did it I kind of understand now.

#42236

Also, here is my contact info
shaheed.jehan712@gmail.com

#42237

Okay cool. ill be emailing you the power point for you to review probably tomorrow by 8 p.m

#42244

Hey idk if youre on open labs but i emailed you the powerpoint for the group project. if you want anything changed just email me.

#42265

Here is a link to the group folder (where we will keep our group work here)