- This topic has 4 replies, 4 voices, and was last updated 8 years, 6 months ago by .
You must be logged in to reply to this topic.
Viewing 5 posts - 1 through 5 (of 5 total)
You must be logged in to reply to this topic.
You must be logged in to reply to this topic.
If a bent coin with probability of a head .3 is tossed 5 times, find the probability of getting
a) exactly 4 heads b) eactly 5 heads c) at most 3 heads [use results from parts a) and b)].
A) Exactly 4 heads= 4-(0.30)^5=3.99757=4
b) Exactly 5 heads= 5-(0.30)^5= 4.99757=5
c) At most 3 heads= 4+5-3(0.3)^5=2.43
Thus, would it be safe to claim the formula for this particular problem is: condition – (probability)^turns?
I got a different answer, using both the formula (n nCr x)(P^x)(1-P)^n-x and Table 2 for Binomial Distributions i got:
a) (5 nCr 4)(.3^4) (1-.3)^1=0.028
b) (5 nCr 5)(.3^5)(1-.3)^0=0.002
c) 0.028+0.002=0.03
1-0.03=0.97
key:parenthesis means multiply and ^ means to the power of (exponent)
Professor please clarify this question and let us know the correct answer as soon as possible.
The last submission (cmax) is correct.
Oruada, a clue that something is wrong is that probabilities always are between 0 and 1. Something close to 0 happens infrequently and something close to 1 is likely to happen.
You must be logged in to reply to this topic.
Ursula C. Schwerin Library
New York City College of Technology, C.U.N.Y
300 Jay Street, Library Building - 4th Floor
Our goal is to make the OpenLab accessible for all users.