- This topic has 3 replies, 3 voices, and was last updated 8 years, 7 months ago by .
You must be logged in to reply to this topic.
Viewing 4 posts - 1 through 4 (of 4 total)
You must be logged in to reply to this topic.
You must be logged in to reply to this topic.
The following data give the speeds (in miles per hour) of 12 cars traveling on a highway.
67 71 57 54 69 74 77 62 61 59 58 63
a. Order the data.
b. Calculate the values of the three quartiles.
c. Find the (approximate) value of the 40th percentile.
d. Find the percentile rank of 62.
e. Construct a box-and-whisker plot.
f. Is the data set symmetric, skewed to the right or skewed to the left?
A)Order the data: 54,57,58,59,61,62,63,67,69,71,74,77
B)values of the three quartiles=Q1=58.5 Q2=62.5 Q3=70
C)value of 40th percentile: x=4/100(12+1)=5.2
d)Percentile rank of 62: 5/12×100=42%
e)
f) This data set is skewed to the right because the mean is greater than the median.
Can somebody tell me why the Q1= 58.5 I thought it will only be 58. What did you guys did sum 57+58 and divide by 2?
I will appreciate your help here. thanks
As I indicated in class, there are many small variations on the procedure of how to get these items. To keep it simple, to find Q1, I am asking that you find the median of the first half of the data. The first half of the data consists of
54, 57, 58, 59, 61, 62
It’s median is (58+59)/2=58.5
For the percentile, the formula is often
n=P/100*N+.5 where P is the percentile and N is the number of data points.
Here we get n=40/100*12+.5=5.3, which rounded to the nearest integer is 5.
In other words the 40th percentile is the 5th element which is 61
Finally, to determine the skewing, you need the mean (not calculated here) together with the median or the box and whisker plot (not here).
You must be logged in to reply to this topic.
Ursula C. Schwerin Library
New York City College of Technology, C.U.N.Y
300 Jay Street, Library Building - 4th Floor
Our goal is to make the OpenLab accessible for all users.