Calculus I

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  • #13242

    Ezra Halleck
    Participant

    True or False: If both and are differentiable at , but then is not differentiable at . If True, why? If False, find .

    This problem involves an understanding of the quotient rule. Also, you must simplify the answer.

    #16866

    Ezra Halleck
    Participant

    false, (f/g)’= (f ‘ g – f g’)/g^2
    (f/g)’ (0)= (f ‘(0) g(0) – f(0) g'(0))/g(0)^2
    =f ‘(0) g(0)/g(0)^2=f ‘(0)/g(0)

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