Calculus I

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  • #13115

    Ezra Halleck
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    Calculate the derivatives of the following functions:

    #16685

    Danielle Telemaque
    Participant

    (d)/(dt) (t^2+1)/(t^2-1), t=-4

    =(2t)/(t^2-1)

    f ‘ (t) = (t^2-1)(t^2)’-(t^2+1)(t^2-1)’/(t^2-1)^2

    f ‘ (t) = (t^2-1)(2t)-(t^2+1)(2t)/ (t^4-2t^2+1)

    f ‘ (t) = (t^3-2t-t^3+2t)/ (t^4-2t^2+1)

    dt= -4, = (4t)/(t^2-1)^2 = (16)/(16-1)^2

    dt= -4, = 16/225

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