In the film Return of the Jedi (1983) , Han Solo who was previously frozen into carbonite is freed by Princess Leah who is in disguise.

How much energy does it take to thaw Han Solo?
solution:  Let’s assume Han Solo has a mass of 180kg.  Carbonite is apparently a form of frozen carbon dioxide which has a melting point of -56.6ºC.  Human body temperature is 37ºC so Han’s body temperature has to be raised ΔT=(37 – -56.6) = 93.6ºC. You can tell Han Solo is very cold from his shaking so he might not be all the way to 37ºC; however, he must be very close Since the human body is mostly water we can just pretend a person is water, but at temperatures below 0ºC water is frozen as ice.  So to calculate the heat needed for this temperature change we need the specific heat of water, c_w = 4186 J/kgºC, the specific heat of ice, c_i = 2093 J/kgºC, and the latent heat of fusion for water, L_f = 333 kJ/kg. Given these facts we can write the heat energy as:

which is a whole lot of energy. In terms of kinetic energy it would be equivalent of changing Han Solo’s velocity by about 82m/s or raising his elevation on Earth by 773 meters.